#include<bits/stdc++.h>
int n, m, a, k;
bool check(int f) {
	int t = 0, b = a;
	for (int i = 0; i < n; i ++) {
		int x = f % 10, y = b % 10;
		if (abs(x - y) == 1 || abs(x - y) == 9) t ++;
		else if (abs(x - y) >= 2) return 0;
		f /= 10, b /= 10;
	}
	return t <= k;
}
int main() {
	scanf("%d%d%d", &n, &a, &k);
	for (int i = 0; i < pow(10, n); i ++)
		if (check(i)) printf("%d\n", i);
	return 0;
}

最简单