1 条题解
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-1
#include<bits/stdc++.h> using namespace std; const int N = 1e5 + 10, inf = 0x3f3f3f3f3f; struct P{ int val, l, r; }; struct T{ int id,sub; bool operator < (const T &t) const { return sub > t.sub; } }; P p[N]; int a[N]; bool vis[N]; long long ans; int main(){ ios::sync_with_stdio(false); cin.tie(0),cout.tie(0); int n, k; cin >> n >> k; priority_queue<T> heap; cin >> a[0]; for (int i = 1; i < n; i ++){ cin >> a[i]; p[i].val = a[i] - a[i-1]; p[i].l = i-1, p[i].r = i + 1; heap.push({i,p[i].val}); } p[0].val = p[n].val = inf; for (int i = 1; i <= k; i ++){ while(vis[heap.top().id]) heap.pop(); T t = heap.top(); heap.pop(); ans += t.sub; int tl = p[t.id].l, tr = p[t.id].r; vis[tl] = vis[tr] = true; p[t.id].val = p[tl].val + p[tr].val - p[t.id].val; heap.push({t.id,p[t.id].val}); p[t.id].l = p[tl].l, p[t.id].r = p[tr].r; p[p[t.id].l].r = t.id, p[p[t.id].r].l = t.id; } cout << ans; return 0; }
信息
- ID
- 1122
- 时间
- 1000ms
- 内存
- 256MiB
- 难度
- 10
- 标签
- (无)
- 递交数
- 4
- 已通过
- 4
- 上传者