2 条题解
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-3
#include <iostream> using namespace std; int n, s; long long t = 10100, c, y, ans; int main() { freopen("yogurt.in", "r", stdin); freopen("yogurt.out", "w", stdout); scanf("%d%d", &n, &s); for (int i = 0; i < n; i++) { scanf("%lld%lld", &c, &y); t = min(c, t); ans += t * y; t += s; } printf("%lld", ans); return 0; }
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-3
#include <bits/stdc++.h> using namespace std; int main() { freopen("yogurt.in", "r", stdin); freopen("yogurt.out", "w", stdout); long long n,s,c,y,ans = 0,now = 0; cin >> n >> s; for(int i = 0;i < n;i ++){ cin >> c >> y; now = min(now,c); ans += now * y; now += s; } cout << ans << endl; return 0; }
- 1
信息
- ID
- 181
- 时间
- 1000ms
- 内存
- 256MiB
- 难度
- 6
- 标签
- 递交数
- 102
- 已通过
- 34
- 上传者