3 条题解
-
-1
#include <iostream> using namespace std;
int dp[200001], a[10];
int main() { long long sum = 0; for (int i = 1; i <= 6; ++i) { cin >> a[i]; sum += a[i] * i; } if (sum % 2 == 1) { cout << "Can't be divided." << endl; return 0; } sum /= 2; for(long long i=1;i<=6;i++){ for(long long j=1;j<=sum;j++){ if(j>=i){ dp[j]=max(dp[j],dp[j-a[i]]*a[i]); } } } if (sum == dp[sum]) { cout << "Can be divided." << endl; return 0; } cout << "Can't be divided." << endl; return 0; }
信息
- ID
- 523
- 时间
- 1000ms
- 内存
- 256MiB
- 难度
- 6
- 标签
- (无)
- 递交数
- 90
- 已通过
- 30
- 上传者